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Commit 0839bff
The symmetry orbitals themselves, not just which irreps appear (#132)
Completes phase 3. The reduction says a1 + t2; the diagram needs the
combinations, so this applies the projection operator
P = (l/h) sum_R chi(R)* R to each orbital of an orbit and picks the
independent results out by Gram-Schmidt.
Checked against what a student writes by hand:
CH4 A1 (1/2, 1/2, 1/2, 1/2) + T2 (3 vectors)
H2O A1 (1/sqrt2, 1/sqrt2) + B1 (1 vector)
SF6 A1g (1/sqrt6 x 6) + Eg (2) + T1u (3)
and on three invariants that would catch a wrong projector without
anyone having to know the answer: the count for each irrep is its
multiplicity times its dimension, the vectors together span the orbit
with nothing left over, and every one is normalised and orthogonal to
the rest.
The totally symmetric one is checked to be the in-phase combination --
every coefficient equal in magnitude -- which is the thing a chemist
would look at first and the thing a sign error would break.
Co-Authored-By: Claude Opus 5 (1M context) <noreply@anthropic.com>
Claude-Session: https://claude.ai/code/session_01EFMUNbw2UpRPmgsqviAowb1 parent 1d57ce6 commit 0839bff
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